Sum of triangular numbers
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Publicado:2026-01-28 15:53:41
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With these 6 pieces, you can build an n·(n+1)·(n+2) solid brick.
The volume of each piece is the sum of the first n triangular numbers.
Therefore, the sum of the first n triangular numbers is:
Σₙ Tₙ = n·(n+1)·(n+2)/6
In the provided STL file, n=6, but you could use the parametric OpenScad file to get any other value.
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